3^4=1^2+x

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Solution for 3^4=1^2+x equation: 



3^4=1^2+x

We move all terms to the left:

3^4-(1^2+x)=0

We add all the numbers together, and all the variables

-(1^2+x)+81=0

We get rid of parentheses

-x+81-1^2=0

We add all the numbers together, and all the variables

-1x+80=0

We move all terms containing x to the left, all other terms to the right

-x=-80

x=-80/-1

x=+80

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